[3(x-2)=10

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Solution for [3(x-2)=10 equation: 



3(x-2)=10

We move all terms to the left:

3(x-2)-(10)=0

We multiply parentheses

3x-6-10=0

We add all the numbers together, and all the variables

3x-16=0

We move all terms containing x to the left, all other terms to the right

3x=16

x=16/3

x=5+1/3

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